Objective:To study the
rise of water in the inverted glass which covers a burning
candle placed in water. Equipment:
three plates, four similar
candles, three drinking glasses of same size.
Introduction:
The experiment described
in the first part is very famous and is used by many teachers
and students to show that there is 21% oxygen in air. In this
demo experiment I will show that the real physics of rising
water is very different.
Procedure:
Put a candle vertically in a plate. Light the candle. Put some
water in the plate so that a small lower portion of the candle
is in water. The candle keeps on burning. Cover the burning
candle by an inverted glass. The candle goes off and water rises
in the glass. How much water will rise in glass depends on the
thickness of the candle and how much time you allowed the candle
to burn before you covered it.
Use a candle and cover it quickly after burning. As the candle
goes off, very small amount of water rises in the glass. It
could be hardly 5% of the volume of the glass. Leave this set up
as it is and take another plate, put a similar candle, pour
water, light the candle and wait for some time. If a fan is
running nearby put it off. Now cover it with a glass of the same
size. This time water rise will be much more.
Now take the third plate and put two candles in it. Pour water
in the plate and light all the candles. Wait for some time and
then cover both by a glass of the same size as used in the
previous trials. This time the water rise will be very high, may
be 40-50%.
What is the Physics of this rising water? When candle burns the
air surrounding the flame becomes hot. The flame itself is very
hot gases. The pressure of this surrounding air is the same as
the atmospheric pressure as all air is connected. As pressure
remains the same and the temperature rises the density goes down
from the gas law PV = nRT. For a given volume n will decrease if
T increases. When you cover the candle(s) you trap this less
dense air. As the oxygen is consumed and the candle goes off,
the air (gases in fact) inside the glass cools down. As the
number of moles n is now fixed, decreasing the temperature will
decrease the pressure and this will suck water in the glass. In
equilibrium the temperature in the glass will be the same as the
room temperature, the pressure will be P= P0-hrg,
where P0 is the atmospheric pressure and h is the
height water rises.
If you cover the candle just after the burning, the air trapped
is not that hot. The density is thus not much lowered and hence
on candle going off the water rise is not much. On the other
hand if you burn two candles together the surrounding air
becomes much more hotter and hence the water rise is high.
Discussion: The experiment described clearly shows that the
rise of water has no relation with the oxygen content in air. In
fact for each oxygen molecule consumed, you produce a molecule
of CO2 among other products. Also the solubility of
CO2 is lower than that of O2. So there is
no question of decrease in pressure inside due to consuming
oxygen.
There is another factor that contributes in rising water in the
glass. At higher temperature the saturation vapour pressure of
water is also high. As the air in the inverted glass is in
contact with water, it will contain saturated vapour. When the
candle goes off and the temperature falls, saturation vapour
pressure also decreases and some of the vapour condenses. This
also decreases pressure inside and helps in rise of water.
Please note that water starts rising only after the candle goes
off.
When to do:
Class 11 while teaching
kinetic theory of gases.
Instrument cost and availability:
Few rupees.